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f(x)=(1-cos(x)^4-sin(x)^2)/(cos(x)^2)−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

1−cos⁡(x)4−sin⁡(x)2cos⁡(x)2\frac{1-\cos\left(x\right)^4-\sin\left(x\right)^2}{\cos\left(x\right)^2}

Step-by-step Solution

1

Applying the trigonometric identity: 1−sin⁡(θ)2=cos⁡(θ)21-\sin\left(\theta \right)^2 = \cos\left(\theta \right)^2

cos⁡(x)2−cos⁡(x)4cos⁡(x)2\frac{\cos\left(x\right)^2-\cos\left(x\right)^4}{\cos\left(x\right)^2}
Why is 1 - sin(x)^2 = cos(x)^2 ?

Final answer to the exercise

cos⁡(x)2−cos⁡(x)4cos⁡(x)2\frac{\cos\left(x\right)^2-\cos\left(x\right)^4}{\cos\left(x\right)^2}

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1−cos(x)4−sin(x)2cos(x)2 
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