$\int\left(x\cdot\sin\left(\frac{1}{3}x\right)\right)dx$
$4^{4x-5}=8^{3x-4}$
$sin^2x+cos2x=-cos^2x$
$7\left(3\right)-1\left(-8\right)-4\left(1\right)$
$2x^2-10x-1=0$
$\frac{dy}{dx}=\frac{x^2}{1+x}$
$-\left(-2n^5x^5d^3\right)^3$
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