∫11x−10−2x+3x2dx\int\frac{11x-10}{-2x+3x^2}dx∫−2x+3x211x−10dx
0=r−10=r-10=r−1
3x3+7x2+3x−1x+1\frac{3x^3+7x^2+3x-1}{x+1}x+13x3+7x2+3x−1
=2(82)=\sqrt{2\left(\frac{8}{2}\right)}=2(28)
∫3xx3−3x2+3xdx\int\frac{3x}{x^3-3x^2+3x}dx∫x3−3x2+3x3xdx
3x=x3+483x=\frac{x}{3}+483x=3x+48
∫8x2+2dx\int\frac{8}{\sqrt{x^2+2}}dx∫x2+28dx
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