$2^x=512$
$3x-12>2x+15$
$\int_0^{10}\left(te^t\right)dt$
$e^{2x}\cdot2e^{2x}$
$z\:+\:-12\:=\:-10$
$\left(2a+b\right)\left(a-b\right)$
$\frac{4}{x^2\left(x+4\right)}$
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