$\left(-10\right)-\left(-7\right)+12$
$\:9\:-\:7\:-\:2\:-\:6\:+\:4$
$\left(10x^{4\:}-6y^9\right)^3$
$9\cdot\left(-1\right)^3+6$
$x-10>\frac{-2}{7}$
$\left(\frac{2}{3}x^2-\frac{1}{5}y\right)^3$
$\int_0^{-\infty}\left(\frac{1}{1+x^2}\right)dx$
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