$\frac{d}{dx}\:\sqrt{y}-2x^3-9y^2+6x=y^3$
$s^2+20s+109$
$\left(-3\right)^4.\left(-3\right).\left(-3\right)^6$
$3x+7\ge9$
$\left(x+12\right)\left(x-5\right)$
$\lim_{x\to+\infty}\left(\frac{2-3x+6x^3}{4-3x^2}\right)$
$\left(20x-2\right)^2$
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