$\lim_{x\to\infty}\left(\frac{2x}{x^2-4}\right)$
$\cot x=\frac{1}{y}$
$4v<-16$
$2x+1\pi$
$\lim_{x\to0}\frac{\left|2+x\right|-2}{x}$
$\frac{x^3+8x^2+17x+136}{8x^2+136}$
$\int-3\left(4^{4-2x}\right)dx$
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