$\left(3w^3+z\right)^2$

$\left(y-5\right)\left(y+8\right)$

$8+\frac{2}{3}x-\frac{4}{15}x-\frac{1}{4}$

$\left(x-1\right)\left(x^3+4x^2+4x-1\right)$

$0.035\left(7\right)^2-0.266\left(7\right)^2+1.005\left(7\right)^2+0.509\left(7\right)+2.986$

$\frac{dy}{dx}=-2\tan\left(2g^2-1\right)$

$\frac{9}{8\:}\:y^5\:\:\frac{2}{6}\:y\:\:\frac{1}{4}\:y^7$