$\left(y-2\right)\left(y^2+2y+4\right)$
$-1\:-1\:+6\:+1$
$\frac{\sin x\cos x}{\tan x\left(1+\sin x\right)}=1-\sin x$
$9^1$
$\frac{-2x^2-5x+12}{x+4}$
$\frac{dy}{dx}=\left(4x^3+2\right)^3$
$\frac{1}{sec-tan}=sec+tan$
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