$\left(4-3x\right)^2$
$\left(5x+4y\right)^4$
$\log\left(x\right)=1.5$
$-\frac{3}{36}x\frac{6}{12}$
$16x^4-y^2$
$5.3333333-\left(0.1\right)^{-1}+0.6666-\sqrt[3]{-0.125}$
$9 y + 6 + 2 ( 5 + y )$
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