$15\cdot19$
$4x^3-18x^2+24x+6$
$\left(-10\right)^{13}$
$\frac{x^2-9x+15}{x^2-5}$
$\int\frac{4x-8}{\left(x-2\right)^2}dx$
$\frac{\sec\left(x\right)}{\tan\left(x\right)\cot\left(x\right)}=\sec\left(x\right)$
$500-123$
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