$y^{''}-10y^'+25y=0$
$3x+3\le-1$
$7y-12\cdot7y-8$
$\int\left(\frac{x}{sec\left(2x\right)}\right)dx$
$1-\cot\left(a\right)=\sqrt{\csc\left(a\right)^2-2\cot\left(a\right)}$
$-2x^2+5x\ge12$
$\sqrt[3]{a^3+3a^2b+3ab^2+b^3}$
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