$\frac{\cos\left(x\right)-cos^3\left(x\right)}{\sin\left(x\right)}=sin\left(x\right)cos\left(x\right)$
$2x^2+x=-5$
$\left(4xy-3pq\right)\left(4xy+3pq\right)$
$0.3+5-0.16-3+14.324$
$\frac{8x\sqrt{12}}{2}$
$5x^4\times20x^4$
$\left(123\right)\left(-6\right)$
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