$\int\frac{1}{\sqrt{49-36x^2}}dx$
$\lim\:_{x\to\:\infty\:}\left(tan\left(6x\right)\right)^x$
$\left(2b^3\right)^2$
$x\left(x-8\right)\:+8>4\:\left(1-x\right)$
$4x^2y-40xy+100y$
$\frac{2^2+2z-3}{z+3}$
$\frac{dy}{dx}=3x^3y^2$
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