$\frac{d}{dx}\:10x+5e^x$
$9-7\left(5x+6\right)>\left(3x+4\right)$
$\ln\left(\frac{x+7}{e^{3x}}\right)$
$\frac{x^3-2x+3}{x^3-9x}$
$9x^2+4y^2-36z^2-18x+16y-72z-11=0$
$3\left(z-7\right)$
$\int\cot\left(25x-3\right)dx$
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