$3x-x^3-4x+5+x^3+4x^2-6$
$-x-9+x-18$
$2y''+3y'-2y=0$
$2\left(5x-3\right)+3\left(10x^2-x\right)-3\left(4x+1\right)$
$\frac{5\cos\left(x\right)}{\sin\left(x\right)}=5\cot\left(x\right)$
$69=\frac{3}{8}x+\frac{1}{6}x+\frac{5}{12}x$
$12ax+8ay$
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