$8a^2+4a-4$
$\frac{270}{-15}$
$4x^3+3x^2+5x+6;\:x=2$
$7x-11\le4x$
$x+10<25$
$12x^5\:\:\:\:8x^3$
$\left(6f-6r\right)\left(2f-9r\right)$
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