$43-\left(-12\right)+\left(-8\right)+40-5$
$6-3+9-5-7+4$
$\frac{729-512b^3}{9+8b}$
$\frac{x^3+3x^2-9x-18}{x^2-9}$
$\frac{m}{s^2}\cdot m$
$\lim_{x\to4}\left(\frac{x^2+x-20}{x^2+x-12}\right)$
$\:\frac{x^3+5x^2+10x+10}{x^2+\:2x+\:1}$
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