$\sqrt{10}\cdot\sqrt{8}$
$6x^2-11x+4$
$x+8>-9$
$m^5m^8$
$2b^2+3a-9b^2+y^2$
$\left(-10\right)\cdot\left(-10\right)\cdot\left(-10\right)\cdot\left(-10\right)\cdot\left(-10\right)$
$\lim_{x\to\infty}\left(\frac{\left(-x^2+4x+8\right)}{9x^4-7x^3+6x}\right)$
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