$-0.6v+3.5=5.3$
$\lim_{y\to0}\left(\frac{\left(1+y\right)^{3}-1}{y}\right)$
$\left(x+8x\right)$
$\frac{3a}{a^4}$
$\left(1.4a+0.3b\right)\left(1.4a-0.3b\right)$
$3x+5=x-7$
$x^2+2<1-2x$
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