$\int\left(x^2\sqrt{3x^3}+1\right)dx$
$\lim_{x\to4}\left(\frac{3x^2-10x-8}{x^2+16}\right)$
$^{y^3}+3y^2-3y-5$
$\lim_{x\to0}\left(\frac{x^3-8}{x-2}\right)$
$y'=\frac{x-y}{x}$
$\frac{dy}{dx}=2\left(3x+5\right)^3$
$6+-3x+1+-1x$
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