$x^2+16x+1=0$
$\left(2j^2k^4\right)^{-2}\left(k^{-1}j^7\right)^6$
$\frac{3a}{b^{-3}}$
$\left(\frac{x^2}{x^4+16}\right)$
$\lim_{x\to0}\left(5+x^2\right)$
$\left(a^2+\:3\right)^3$
$\left(p^{-4}\right)^6$
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