$8m^2-12mn$
$e^{-x}y'=x^3$
$\left(r+8\right)^2$
$\int_2^6xdx$
$\frac{\left(-25z^9\right)}{\left(5z^2\right)}$
$\int x\left(sec\left(x\right)^2-sen\left(x\right)\right)dx$
$2\left(x+3\right)=98$
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