Since sin\sinsin is the reciprocal of csc\csccsc, 1×10−6(sin(1×10−6))2\frac{\sqrt{1\times 10^{-6}}}{{\left(\sin\left(1\times 10^{-6}\right)\right)}^2}(sin(1×10−6))21×10−6 is equivalent to 1×10−6⋅(csc(1×10−6))2\sqrt{1\times 10^{-6}}\cdot {\left(\csc\left(1\times 10^{-6}\right)\right)}^21×10−6⋅(csc(1×10−6))2
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dudx+y=0\frac{du}{dx}+y=0dxdu+y=0
x2−2x−169x^2-2x-169x2−2x−169
x2−9x=−14x^2-9x=-14x2−9x=−14
12 cot2(x) = 412\:cot2\left(x\right)\:=\:412cot2(x)=4
(1+x)12dydx=xy3\left(1+x\right)^{\frac{1}{2}}\frac{dy}{dx}=xy^3(1+x)21dxdy=xy3
∫y−2y−3dy\int\frac{y-2}{y-3}dy∫y−3y−2dy
x4+0+9x2+4x+12x^4+0+9x^2+4x+12x4+0+9x2+4x+12
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