$3x\left(x^{2}+6\right)$
$5\left(4x-3\right)$
$15\:sin2x^{\circ}\:=\:10cosx^{\circ}\:$
$8\:-2\sqrt{16-15}$
$18.7-5.46-3.418$
$\lim_{h\to0}\left(\frac{\left(4+h\right)^2-16}{h}\right)$
$\int\frac{x^3+3x-2}{x^2-x}dx$
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