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Exercise

$\frac{\sin\left(2x\right)}{\cos\left(x\right)}-1=0$

Step-by-step Solution

1

Apply the formula: $a+\frac{b}{c}$$=\frac{b+ac}{c}$, where $a=-1$, $b=\sin\left(2x\right)$, $c=\cos\left(x\right)$, $a+b/c=\frac{\sin\left(2x\right)}{\cos\left(x\right)}-1$ and $b/c=\frac{\sin\left(2x\right)}{\cos\left(x\right)}$

$\frac{\sin\left(2x\right)-\cos\left(x\right)}{\cos\left(x\right)}=0$

Final answer to the exercise

$\frac{\sin\left(2x\right)-\cos\left(x\right)}{\cos\left(x\right)}=0$

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