$\frac{x^3}{x-3}$
$x^3-6x^2-x+6$
$a^4x-b^4x-2b^2x$
$\frac{d^2y}{dx^2}=\frac{4x^5}{5}-7x$
$\left(6p-2r\right)$
$3^4.\:3.^23^8$
$\sec\left(x\right)=tan\left(x\right)+\left(\frac{cos\left(x\right)}{1+sen\left(x\right)}\right)$
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