$\frac{1-\left(\frac{1}{x+1}\right)}{x-\left(\frac{1}{x+1}\right)}$
$\left(3c-1\right)^2$
$x-\frac{x}{x+7}=\frac{7}{x+7}$
$\left|-8\right|>-\left(-5\right)$
$\int x^2\left(5x+8\right)^6dx$
$\left(\:-\:2\:\right)\left(\:2\:\right)\left(\:5\:\right)\left(\:-\:5\:\right)$
$23x-6<4x+2$
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