$\frac{9x^2+6x+1}{3x+1}$
$\frac{15b^4}{3b^4}$
$158+72$
$\frac{dy}{dx}\left(2x+3\right)^5\left(x-5\right)^3$
$3x+2x+3y\:-\:7y$
$y=\frac{1}{3}x^3-6x^2-3$
$\left(1-t^2\right)\frac{de}{dt}+et=0$
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