$20ab^2-10b^2c$
$\left(6a-16m\right)^2$
$\frac{16x^5-8x^3+20x}{4x}$
$\frac{-12x^{10}y^3}{6x^8y}$
$\left(y\right)^'\:+\left(sinx\right)y\:=\:2xe^{cosx}$
$-465+365-594+235-562$
$x^2+\frac{3}{4}x=0$
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