$\frac{x^3+3}{x+3}$
$\left(3b^2-4c\right)^2$
$-\sec^2y+\csc^2y$
$x^2+2xy+y^2-2^2$
$1+1+1+1+1\cdot0+11$
$g-7=15$
$\lim_{x\to2}\left(x^2+3x+1\right)$
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