$\int e^{6\sqrt{x}}dx$
$-6\cdot12-5-3\cdot5-3$
$-2+3\cdot2-53-3-5+2-2\cdot3-4$
$\int\frac{\sqrt[3]{x}+3}{x}dx$
$7x+4x^2-3\:entre\:x-3$
$\left(4x+3\right)\left(4x-3\right)^2$
$0=-3$
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