$c^2-2ac+2b;\:a=-2;\:b=-3.c=-\frac{1}{2}$
$4x^2-4x+9$
$\left(\frac{3}{4}a^3b^2\right)^2$
$12b-5<8b+7$
$\left(5d+2c\right)^2$
$\cosh\left(2x\right)=2\sinh^2\left(x\right)+1$
$\left(4x-4\right)\cdot\left(-2\right)$
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