$16x^2+2x+4$
$\int\:\:e^{cost}\:sent\:dt$
$-12\:+\:7\:-\:6\:-\:10\:+\:3\:+\:4\:+\:2$
$\int\left(\frac{\left(-5e^{-5x}\right)}{\left(e^{-5x}+5\right)^4}\right)dx$
$36m^2+60mn+16n$
$\:\frac{40}{5}$
$\sqrt{\left(12-x\right)}=x$
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