$\frac{1}{\sin\left(x\right)}+\cos\left(x\right)$

$\left(9+y^2\right)\frac{dx}{dy}-1=0$

$\left[5-7.\left(-3\right)-\left(5-3\right)\right]$

$y'\:+xy+x=0$

$\int e^x\left(6+4e^x\right)^4dx$

$6x=7+5x$

$\left(\frac{3^3x^0y^{-2}}{2^3x^3y^{-5}}\right)^{-1}\left(\frac{3^3x^{-1}y}{2^2x^2y^{-2}}\right)^2$