dydx=x5y(lny)5\frac{dy}{dx}=\frac{x^5y}{\left(lny\right)^5}dxdy=(lny)5x5y
2⋅limx→0((x)(lnx+2x))2\cdot\lim_{x\to0}\left(\frac{\left(x\right)}{\left(\ln x+2x\right)}\right)2⋅x→0lim((lnx+2x)(x))
(24−y)2( 24 - y ) ^ { 2 }(24−y)2
∫9xe3x2+2dx\int9xe^{3x^2+2}dx∫9xe3x2+2dx
m−18=42m-18=42m−18=42
−2x23+5y312-\frac{2x^2}{3}+\frac{5y^3}{12}−32x2+125y3
b3+ 3bb^3+\:3bb3+3b
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