$5\cdot\left(-10\right)+6\::2$
$\frac{b^2-4b-12}{\:b+2}$
$\frac{dy}{dx}=e^{-16t}\:y\left(0\right)=3$
$\frac{1+\sec\left(4x\right)}{\sin\left(4x\right)+\tan\left(4x\right)}$
$\csc2x=\cot x-\cot2x$
$\left(3c+4\right)^2$
$2y-6x+9-3y-10$
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