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$\frac{\left(4x^4-4x^3+6x^2-4x+5\right)}{\left(x^3-2\right)}$

Final answer to the exercise

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Other solved exercises

$x-4=-34$

$\left(4-13x^2\right)^2$

$\left(40\right)-\left(-4\right)$

$-42\cdot7$

$\frac{x^2}{x-4}$

$\left(45.89\right)^3\cdot640.8$

$2z\:+\:2y\:$
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