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$\frac{\left(3x^2-4x+5\right)}{\left(x-1\right)\left(x^2+1\right)}$

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$5\left(\left(-4\right)+\left(-3\right)\right)+8$

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$125y^3-1$

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$x^2-4xy+4y^2-1$

$30n+150=180$
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