$\frac{x+8}{2}=x-10$
$6a^3-2a^2+8a$
$\left(ab^{-3}\right)^{-1}$
$x^2=6-x$
$\frac{2}{4}x^2$
$-\left(-8\right)+\left(+1\right)$
$\left(2x+5\right)\left(2x+10\right)$
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