$\frac{3}{3x}\:.\:\frac{y}{5x}$
$\frac{1}{3}x^2-\frac{1}{4}x+3;\:x=12$
$\:\left(\:13x^2\:+\:10y^2\right)^2$
$\left(\frac{3b^2}{a^{-2}}-\frac{a^{-3}}{b^2}\right)^2$
$\frac{dy}{dx}=-x^{2}y^{2}$
$\frac{dy}{dx}=-8\cdot y\cdot x+4\cdot x$
$-\frac{225}{-15}$
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