$5x-3>4x-8$
$\lim_{x\to\infty}\frac{x-\arctan\:\left(x\right)}{e^x\:+\:4x}$
$\left(x-2\right)\left(x-3\right)\left(x+4\right)\le4$
$\left(2a-b^x\right)\left(2a+b^x\right)$
$3x^2+5x-4=x+3$
$-\sqrt[2]{100}$
$1+a+a^2+a^3+a^4+a^5$
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