$\left(2x^3+4y^2-6x\right)\cdot\left(2x^3-6y^2-2\right)$

$\frac{4}{2.0045}+\frac{22}{3}$

$2\left(-\frac{7}{2}\right)^5-\left(-\frac{7}{2}\right)^4-36\left(-\frac{7}{2}\right)^3-36\left(-\frac{7}{2}\right)^2-38\left(-\frac{7}{2}\right)-35$

$x^2-10x=21$

$\:n\:+\:8\:<\:2n$

$9x^2+5xy$

$\lim_{x\to0}\left(\frac{\left(4e^{\left(6-2x\right)}-x^2\right)}{\left(x\right)}\right)$