$\left(-3a^2b^4c^6\right)^2$
$\frac{dy}{dx}-\frac{y}{x}=x^3$
$\left(x^4y+6x^3y^2\right)^2$
$\int\frac{3x-16x-3}{x^3-2x^2-3x}dx$
$\int19xsec^2x\:dx$
$\int\left(\frac{e^x-e^{-x}}{2}\right)\:dx$
$x^2-34x=73$
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