$\int\frac{3x}{\left(6x+5\right)^5}dx$
$\int\frac{5x-4}{\left(x-7\right)^{\frac{8}{3}}}dx$
$\lim\:_{x\to\:\:0}\left(\frac{tan\left(x\right)^2}{x}\right)$
$x^3\cdot8x^3$
$\frac{dy}{dx}=e^{-2y}$
$5cosx+6=10cosx+5$
$xy'=45$
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