$\left(t-5r\right)^3$
$\int\sqrt[3]{1-5x}dx$
$\left(-1\right)\cdot\left(-18\right)$
$125x^6-y^{12}$
$96\cdot3.5$
$\lim_{x\to\infty}\left(\frac{-4ln\left(x^5\right)}{\sqrt[3]{5x+19}}\right)$
$\int\frac{x^2}{x^2+5x-24}\:dx$
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