$-5+\left|7-2\left(1-9\right)-3+12\right|+4$
$\left(x^2+1\right)\tan\left(y\right)\frac{dy}{dx}$
$\left(-8a^9b^3\right)\left(-6a^6b^3\right)$
$\frac{dy}{dx}=\frac{1}{34}\left(15-y\right)$
$\frac{6x^2+7x-5}{4x^2+6x-4}$
$\frac{15x-4}{2}<1+6x$
$100a^4-60^2b+9b^2$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!