$4.\left(-2\right)+\left(-2\right).\left(-3\right)-\left(+5\right).\left(-4\right)-8.\left(-3\right)$
$2^{x+1}-4^{x+1}=0$
$-\:\left(-5+6-3+6\right)+3-\left(+5-2+1\right)$
$a^2+22a+22$
$a^3=w$
$x^2+11x+28+x\left(-x-5\right)<-8$
$\frac{x}{\:x+2}-\frac{1}{x-2}=\frac{8}{x^2-4}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!