sec2x+7secx+6=0\sec^2x+7\sec x+6=0sec2x+7secx+6=0
∫01(x2)− ∫01(x)dx\int_0^1\left(x^2\right)-\:\int_0^1\left(x\right)dx∫01(x2)−∫01(x)dx
{(10x3)2}5\left\{\left(10x^3\right)^2\right\}^5{(10x3)2}5
−x−3.y-x-3.y−x−3.y
2(3)−2−42\left(3\right)-2-42(3)−2−4
t2−4t+8\frac{t^2-4}{t+8}t+8t2−4
49x4−6449x^4-6449x4−64
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