$3x+1\:entre\:2x-4$
$\frac{dy}{dx}\left(-5y\right)=-\frac{5}{2}xy^3$
$\frac{x^3-2x^2-3x+2}{x^2-5x+6}$
$\ln\left(\sqrt{2x-5}\right)$
$\tan x\sec x=\tan x$
$6\cdot x+6\cdot7$
$\frac{1}{2\pi}\cdot\sqrt[2]{\frac{k}{m}}$
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